divide by 10

[Newz2000]

Good idea, but this particular chip seems to assume you don't need Q0 - Q2 and therefore doesn't assign them to pins. It starts with Q3. This blew me away for a moment - and why did they leave out Q10?

But regardless, I think the chip is dead. Q3 is always off and the other Qs are always on. I'm going to give it one more go tonight and then ditch it I think.

Drat that 12v bus. I guess this is the hazard with working on circuits that use both regulated and unregulated voltages. You have to be uber-careful that you connect to the right place.

Maybe I should make all the easy-to-reach busses on my breadboard regulated and reserve the hard-to-reach bus for unregulated. That way I'd have to be much more deliberate when grabbing unregulated voltage.

[jimandy]

Actually, in my 4060 data sheet the lowest order bit available (divide by16, pin 7) is designated Q4, but for your purposes it wouldn't matter. Using Q4 & Q5 at a higher speed will give the same result as using the non-existent Q1 & Q2 at a lower speed.

Of course if the chip is fried, all the Q's are now "Qrap". (Sorry, couldn't resist).

<small>[ November 11, 2005, 10:27 AM: Message edited by: jimandy ]</small>

[MrAl]

Hi there,

Matt, another idea is to use a pulse stretcher.
A pulse stretcher has an advantage over standard
divider chips because it can be adjusted to trigger
on any number of pulses by a simply pot adjustment.
Thus, you can get divide ratios of 8,10, 16, or
even 20 if you want that, using the same circuit.

If you have another 555 handy you can use that
for the stretcher.

Also, there are lots of applications on data
sheets when you look up the parts on the web
which might help for some things.


Take care,
Al

[HighFrequency]

I just quickly scanned through this, and it's a little old, but:

You don't need to hook your output pin to reset, the output pin will always be on half of the time, just at different frequencies. Just let the counter do it's thing.