T&L Publications

I understand that electrons flow from negative to positive, and current flows against the diode arrow. What I can't figure out is when the book asks, " will the output be negative or positive", when a diode is put in a circuit with an ac source. If the anode is hooked up to the ac source a...

I’m reading a textbook on electronics, and I’m in the diode section. They show a circuit with one diode and a resistive load. The cathode is facing away from the AC voltage source. There is an arrow showing the current moving counter clockwise, and it says that only the positive half of the wave wil...

WHAT IF ONE OF THE UNKNOWN INDUCTORS MIGHT BE AROUND 500 MICRO FARADS, HOW DOES THAT EFFECT THE SIZE OF RESISTOR I SHOULD USE AND FREQUENCY I NEED TO START WITH?<p>THANKS,
BRAD

Analogee: I HOOKED UP THE CIRCUITS LIKE YOU DISCRIBED. IF I USE A1K-OHM RESISTOR, AND ADJUST THE FREQUENCY SO I HAVE EQUAL VOLTAGE DROPS ACROSS BOTH THE RESISTOR AND THE INDUCTOR. AT THAT FREQUENCY THE INDUCTIVE REACTANCE SHOULD BE 1K OHMS. SO IF I SOLVE FOR L IN THE XL FORMULA, AND USE 1K AND THE F...

WOW. YOU GUYS HAVE GIVEN ME A TON OF GREAT INFORMATION AND IDEAS. THANKS A BUNCH<p>BRAD.

I need to figure out how to tell the value of an inductor. I have three different sizes but I don’t know how to tell how many henrys they are. Can anyone out there tell me how?

Thanks,<p>Brad.

I HAVE A CIRCUIT DRAWN ON ELECTRONIC WORKBENCH, AND I NEED SOME HELP WITH IT. IS THERE A WAY TO PASTE OR ATTACH IT TO THE MESSAGE SO IT WILL SHOW UP ON THIS FORUM SO SOMEONE CAN HELP ME? <p>THANKS,
BRAD

The symbol on most of parts is two wavey lines. The other sign I belive is the sign for Motorola.
Thanks for any help.
Brad

How do I know who made a certain part? I have part numbers that start with 1N and 2N and LM is there a code to find out who made these parts?

Can anybody tell me how to read electrical component, other than resistors? I have some but don't know what they are or there value. If you can not tell me, do you know of a website that would be able to help?

Thank you;