Search found 6 matches

by vineo76
Sun Mar 22, 2009 3:37 pm
Forum: Projects & Kits
Topic: XBee OEM RF whip antenna modules?
Replies: 0
Views: 1592

XBee OEM RF whip antenna modules?

I'm currently using the maxstream xb24-dks usb development board. But it seems like there is no software communication between the board and the XTU software. The port works fine. It powers up the board. But it seems like there is a baud rate problem. I am trying to program a XBee OEM RF whip antenn...
by vineo76
Sat Mar 21, 2009 7:12 pm
Forum: Projects & Kits
Topic: Wireless weather station(Sept. 2007)
Replies: 1
Views: 1584

Wireless weather station(Sept. 2007)

I am current trying to do the September 2007 wireless weather station project part 1. But every time I go to step four it never works. It can read whats on the modules, but it can't write anything to them. I know I have all the write parts as warned and instructed about in the article. But every tim...
by vineo76
Mon Feb 16, 2009 10:59 am
Forum: Projects & Kits
Topic: AVR Butterfly Power problem; Smileys workshop
Replies: 0
Views: 1410

AVR Butterfly Power problem; Smileys workshop

I forgot that it actually matters where you wire the ground on the AVR butterfly. I put the positive lead in the right place. but I out the negative lead from the batter box two places to the left from where I was supposed to put it as shown in the August 2008 issue of nuts and volts. The LCD screen...
by vineo76
Wed Feb 11, 2009 4:24 pm
Forum: General Discussion
Topic: Quadratic Equation help?
Replies: 5
Views: 1237

Re: Quadratic Equation help?

If instead we assume you meant this: -para(20000,Rd)/(3000-Rd+350)=-4 then we get this quadratic: -4*Rd^2-86600*Rd+268000000=0 the two possibile solution are: Rd=-25*sqrt(294689)-10825 Rd=25*sqrt(294689)-10825 and again the second one is the right one, which gives us Rd=2746 ohms. I meant the one ab...
by vineo76
Tue Feb 10, 2009 9:09 pm
Forum: General Discussion
Topic: Quadratic Equation help?
Replies: 5
Views: 1237

Quadratic Equation help?

Can someone show me step by step how to put this in quadratic form?
its specifaclly for JFET design by the way (Common Source Amplifier)


A(v) = -(20k||R(d) / 3k-R(d)+350=-4


where k is for kilo ohms..

how do I put it in quadratic form?

Can you show me step by step?
by vineo76
Fri Feb 06, 2009 7:37 pm
Forum: Projects & Kits
Topic: A Touch of Spice
Replies: 3
Views: 2391

Re: A Touch of Spice

Thanks for the info..I was trying to figure it out all weekend...I was wondering why it didn't work. I'll try the project again.