T&L Publications

4 days. It was output enable?

CAT-5 or CAT-6 patch cords are of stranded wire.

You need a better spec sheet, like - https://www.onsemi.com/pdf/datasheet/mc74hc595a-d.pdf (not from TI, but is for the "A" part (74HC585 A )) Also needed - A schematic diagram of your circuit. My first EWAG based on limited info provided is OUTPUT ENABLE pin needs to be pulled up. side comment - Th...

agreed!

I asked "Do you want re-triggerable?" He answered "Yes". Which is wrong based on rest of answer. "Re-trigger" does not ignore triggers during time period. You said the "yes" was to the "Ignore"; but that was not the question! Please learn to READ before butting in! Back to post 1 - regardless of if ...

additional triggers do not exceed the Delay Time Then the answer is NO. You want additional triggers during the delay ignored till after the delay, Then another trigger starts a new delay. "Re-trigger" means the output could stay on forever, as long as triggers happen before the delay time since th...

It can be either way. Re-triggerable takes a couple transistors; one to discharge the timing capacitor to start the time over again.

Do you want re-triggerable?

Cheers,

Haklesup, It says that it has been discontinued.

How would he know? Requires reading.

Pin 6 would be the pin for the connection missing a pin number.

Pin 5 is also not shown, but is the junction of internal voltage divider, so does not need to be used in this case.

Cheers,

The load is 15 ohms at 120 Volts and 12 amps DC.

Does not compute!

120V / 12A = 10 Ohms

Or, if the 15 Ohms is correct, then 12Amps is wrong; like JWax said.

I have never of anything needing 110VDC at 12 Amps. (probably why no vendor makes one)

And not safe unless isolated from mains.

What is the load?

How are you regulating the output to 110VDC? The peak of 110VAC is 155V. At no load that is what the filtered DC will be. As load current increases, output ripple voltage increases as the filter capacitor supplies the current between the input voltage peaks. The input current is zero till the input ...

Not getting 10mA (max) into a load is a problem. It looks like IC fails in this respect.

Getting a smaller short circuit current is a good thing. Why are you worried that? When output voltage is forced to zero (by short) the IC probably limits the current so it does not destroy itself.

Where are you seeing 27mA in the spec.

Last item in specs for each part number. In this case on page 5 of 24. And resolved subject line problem in post 2.

Now I missed a line on spec sheet - Load Regulation, Conditions column; which shows 0ma to 10mA.

Where did you get the IC? Discount places sell parts that failed some test but still function.